20. Which term of the arthmetic
progression 3,11,19,27 ....... is 547 ?
Answer:
Answers
Answered by
2
Answer:
. ..................................
Attachments:
Answered by
0
answer is: the 69th term
Explanation:
a=3
d=a1-a=11-3=8
an=547
using formula:
an=a+(n-1)d
547=3+(n-1)8
547-3=(n-1)8
544/8=(n-1)
68=(n-1)
68+1=n
I.e n=69
therefore, the 69th term of arithmetic progression is 547
Similar questions