Math, asked by nabingautam724, 1 year ago

20 worker can finish a piece of work in 24 days. After working for 6 days some worker were added, the work was completed in 21 days in total. Find out number of worker added.

Answers

Answered by Hemanth98675
2

Prakhargupta3301 Ace

Look at it this way:

20 workers ---- do 1 work -----30 days

20 workers ---- in 1 day    ----- 1/30 of whole work

1 worker     ---- in 1 day    ----- 1/600 of whole work

15 workers ---- in 1 day    -----  (1/600)*15= 1/40 of whole work

We know they collectively worked for 35 days overall.

So x+y= 35 -------- eqnⁿ (1)

Suppose that 20 workers worked for x days, and that 15 workers (after 5 left) worked for y days. 

So:

As 20 worked for x days and 15 for y days and completed 1 whole work:

{[x·(1/30)]+ [y·(1/40)]} = 1 

(x/30)+ (y/40)              = 1

(4x+3y)/ 120                = 1

4x+3y                           = 120    eqnⁿ (2)

From eqnⁿ (1):

x+y= 35

x    = 35-y                 

Putting this value in eqnⁿ2:

4 (35 - y)+ 3y = 120

140 - 4y +3y   = 120

y                     =  20 days

x= 35- y ⇒ 15 days

We can infer that:

 

20 workers will first do work for 15 days, then 5 workers will leave and then remaining 15 workers will complete the work in 20 days. Total time taken will be 35 days.

Hence, the answer to the question is 15 days.


alien3dgaurav: Check question once again.. Question is different & u have answered different thing..
Hemanth98675: Oooh sorry
Answered by alien3dgaurav
0

Answer:

Step-by-step explanation

20×18÷15= 24

So 4 workers were added extra


nabingautam724: Can u solve it with languages
alien3dgaurav: First let me know is my answer correct?
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