Question

20. Write the discriminant of the equation
3x + 4x - 5 = 0 and honce find the nature
of roots.​

Answer 1

Step-by-step explanation:

3x+4x-5=0

then the power of 3x is 2

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Answer 2

Answer :

• D = 76
• There are 2 distinct root.

Given :

• 3x + 4x - 5 = 0

To find :

• Nature of roots

Solution :

3x + 4x - 5

We know that , Qudratic equation ax² + bx + c So, comparing equation with ax² + bx + c = 0 we Get,

• a = 3
• b = 4
• c = -5

We know that discriminant formula :

• D = b² - 4ac

Where, D is discriminant , b is 4 , a is 3 and c is -5

Substituting the value :

➞ D = b² - 4ac

➞ D = (4)² - 4(3) × (-5)

➞ D = 16 - 12 × (-5)

➞ D = 16 - (-60)

➞ D = 16 + 70

➞ D = 76

So, D > 0

There are 2 distinct root.

Verification :

➞ D = b² - 4ac

➞ 76 = (4)² - 4(3) × (-5)

➞ 76 = 16 - 12 × (-5)

➞ 76 = 16 - (-60)

➞ 76 = 16 + 60

➞ 76 = 76

Hence Verified

More Explanation :

• D < 0 are no real roots
• D = 0 are two equal real roots
• D > 0 are two distinct real roots