Math, asked by navyapokle, 9 months ago

20/x+y +3/x-y = 7
8/x-y - 15/x+y= 5

Answers

Answered by theravi18
1

Answer:

20/x+y + 3/x-y =7 & 8/x-y - 15/x+y =8

Now, we have 2 equations and 2 variable ie, it is clear that we can solve it by

hit & trail method

Just put x=3 & y=2 it will satisfy both the equations.

How this logic comes i will explain.

look at 20 it is multiple of 5. Hence, we can directly imagine a no. whose sum is 5 ie. (x+y=5) then numbers can be 3 & 2 respectively.

Good luck.

Answered by khushitahlani
1

Answer:

x=3:y=2 these is the answer.....

let 1/x+y=a:1/x-y=b

let 1/x+y=a:1/x-y=b20a+3b=7

let 1/x+y=a:1/x-y=b20a+3b=7-15a+8b=5

let 1/x+y=a:1/x-y=b20a+3b=7-15a+8b=5solve these equations :by substitution method or cross multiplication method or the method you know you will get a=41/205:,b=1 substitution the value that we have let above (1/x+y..........

let 1/x+y=a:1/x-y=b20a+3b=7-15a+8b=5solve these equations :by substitution method or cross multiplication method or the method you know you will get a=41/205:,b=1 substitution the value that we have let above (1/x+y..................)you will get the values of x, y

let 1/x+y=a:1/x-y=b20a+3b=7-15a+8b=5solve these equations :by substitution method or cross multiplication method or the method you know you will get a=41/205:,b=1 substitution the value that we have let above (1/x+y..................)you will get the values of x, yby #khushi.........hope you found it easy to do

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