Question

20(y+1)(4y2 – 9) by 4(2y – 3 )​

Answer 1

Answer:

20(y+1)(4y²-9)/4(2y-3)

5(y+1)(4y²-9)/2y-3

(5y+5)(4y²-9)/2y-3

5y(4y²-9)+5(4y²-9)/2y-3

20y³-45y+20y²-45/2y-3

2y-3)20y³+20y²-45y-45(10y²+25y+15

-(20y³-30y²)

50y²-45y-45

-(50y²-75y)

30y-45

-(30y-45)

0

quotient =10y²+25y+15 and remainder =0

Answer 2

Hope it helps...!!!!