Question

20(y+4)(y²+5y+3)/5(y²+5y+3) . only answer the ticked ones. this is from the chapter factorization. pls do not ignore

Answer 1

$\textbf{ Hello Mate! }$

$= \frac{52pqr(p + q)(q + r)(r + p)}{104pq(q + r)(r + p)}$

On cancelling,

Let's divide, 52pqr / 104pq = 1r / 2

Rest, ( q + r )( r + p ) got cancelled.

So we get,

$= > \frac{1r(p + q)}{2}$
Similarily,

$= \frac{20(y + 4)( {y}^{2} + 5y + 3)}{5(y + 4)} \\ = 4( {y}^{2} + 5y + 3)$

Moreover,

$= \frac{x(x + 1)(x + 2)(x + 3)}{x(x + 1)} \\ = (x + 2)(x + 3)$

⭐ Rembering point : Factorising means that terms should be in multiplication.

Have great future ahead!