Question

20. यदि समीकरण kx(x-2)+ 6 = 0 के मूल बराबर हों, तो k का मान ज्ञात कीजिए।​

Answer 1

Answer:

kx(x−2)+6=0

kx2−2kx+6=0

Since the roots are equal,

⇒b2 =4ac

(−2k) 2 = 4(k)(6)

4k2 = 4k(6)

∴k=6

please follow me make me as brainlist and like my answers also.......