Question

20 years ago a father was four times as old as his son and after 4 years he will be twice as old as his son what are their present ages​

Answer 1

hey mate here is ur answer

Let the son be X years old and the father Y years old now

Y = 4X

In twenty years

Y +20 = 2(X + 20)

Y + 20 = 2X +40, substitute the present age, Y = 4X into the equation

4X+20 = 2X +40

2X = 20

X= 10

The father is 40 years old and the son is 10 years old

plz mark as Brainliest dear friend