Question

20 years ago a father was four times as old as his son and after 4 years he will be twice as old as his son. What are their present ages?
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Answer 1

Required Answer:-

Father present age = 68 years , Son's present age= 32 years

Process to find :-

Let the father's present age be x and Son's present age be y

According to the problem ,

i) (x - 20) = 4(y-2)

4y-x = 60

ii) x+ 4=2(y+4)

x-2y=4

By Solving the equation we get :

x= 68

y= 32

Therefore the Present ages of father and his So s are 68 and 42 respectively

Answer 2

Answer:

Present age of father : 68 years

Present age of son : 32 years

Hope it helps :-)