Question

200,166⅔,142 6/7,_?,111 1/9​

Answer 1

I don’t know sorry okkkkk

Answer 2

Answer:

The missing fraction is $\frac{1000}{8}$ .

Step-by-step explanation:

Given the fraction, as follows:-

$200 \hspace{0.3cm}, \hspace{0.1cm} 166 \hspace{0.1cm}\frac{2}{3} \hspace{0.3cm} , \hspace{0.1cm} 142 \hspace{0.1cm}\frac{6}{7} \hspace{0.3cm} , \hspace{0.1cm} - \hspace{0.3cm} , \hspace{0.1cm} 111\frac{1}{9}$

Let the missing value be x.

Converting the above-mixed fraction into a simple fraction, we get

$200 \hspace{0.3cm}, \hspace{0.1cm} \hspace{0.1cm}\frac{500}{3} \hspace{0.3cm} , \hspace{0.1cm} \hspace{0.1cm}\frac{1000}{7} \hspace{0.3cm} , \hspace{0.1cm} x \hspace{0.3cm} , \hspace{0.1cm} \frac{1000}{9}$

We see that all the fractions have the numerator as a factor of $1000.$

Therefore, to convert the numerators to 1000, we need to multiply $200$ by $5$ and $500$ by $2$. Along with that denominator also has to be taken care of.

$200$ ⇒     $200\times\frac{5}{5}$       =   $\frac{1000}{5}$

$\frac{500}{3}$  ⇒     $\frac{500}{3} \times \frac{2}{2}$

Now write the fractions,

$\frac{1000}{5} \hspace{0.3cm}, \hspace{0.1cm} \hspace{0.1cm}\frac{1000}{6} \hspace{0.3cm} , \hspace{0.1cm} \hspace{0.1cm}\frac{1000}{7} \hspace{0.3cm} , \hspace{0.1cm} x \hspace{0.3cm} , \hspace{0.1cm} \frac{1000}{9}$

Since all the  numerators are the same, it is clear from above that we just need to check the pattern of the denominators as

$5,6,7,x,9$

The missing value in this is $8.$

Hence, the missing fraction is $\frac{1000}{8}$ .

#SPJ2