Math, asked by sakshipansari12, 7 months ago

200= 3y + 2y^2/100 how to solve this ​

Answers

Answered by kotapatiharsha
1

Step-by-step explanation:

please mark it as brainliest

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Answered by bangardhruvi
1

Here's your answer

Step-by-step explanation:

200=3y +2y^2/100

= 200*100= 3y+2y^2

=20000=3y +2y^2

  • =20000/3=y

=13333.3dash

  • =20000/2=y^2                                                                                                                            =10000

Hpe it helps you.

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