Question

200 cm of an aqueous solution of a protein contains 1.26 gol
protein. The osmotic pressure of such a solution at 300 K is fon2
be 2.57 x 10 bar. Calculate the molar mass of the protein.​

Answer 1

SOLUTION

According to Van't Hoff equation,

π = cRT

=) n/V RT

=) wB RT/MB V

=) MB= wB RT/MB V

Given,

V= 200cm^3 = 0.20litres,

wB= 1.26g,

T= 300K

R= 0.083LbarK^-1 mol^-1

π= 2.57×10^-3 bar

Therefore,

MB= 1.26×0.083×300/2.57×10^-3×0.20

=) 61039gram mol^-1

hope it helps ✔️

Answer 2

$\huge{\boxed{\boxed{\mathscr{\purple{ANSWER}}}}}$

We know that ,

PV = nRT

PV = mRT/W

W = mRT/PV

W = 1.26 x 10^-3 x 300 x 0.083/2.57 x 10^-3 x 0.2

W = 61 kg/mol

Thanks ❤️