200 cm³ of a gas A diffuse in the same time as 300 cm³ of gas B .if the molecular mass of B is 32.calculate the molecular mass of gas A
Answers
Answered by
6
Answer:
24g/mol
Explanation:
according to Graham law of diffusion
RA/RB = (MB/MA)^1/2
(200/t)/(300/t) =( 32/MA)^1/2
4/3 = 32/MA
MA= 32×3/4 = 24 g/mol
Answered by
0
Answer
according to graham law of diffusion
Attachments:
Similar questions