Question

200 find perfect cube using prime factorization​

Answer 1

• Answer:

The value of the cube root of 200 rounded to 7 decimal places is 5.8480355.

It is the real solution of the equation x3 = 200.

The cube root of 200 is expressed as ∛200 or 2 ∛25 in the radical form and as (200)⅓ or (200)0.33 in the exponent form.

The prime factorization of 200 is 2 × 2 × 2 × 5 × 5, hence, the cube root of 200 in its lowest radical form is expressed as 2 ∛25.

• Cube root of 200: 5.848035476
• Cube root of 200: 5.848035476Cube root of 200 in Exponential Form=(200)⅓
• (200)⅓Cube root of 200 in Radical Form: ∛200 or 2 ∛25

3√200 =3√(2×2×2)×5×5

2 cube√25

=5.848

here is your complete ans