Question

200 g of ice at -20 degree Celsius is mixed with 500g of water at 20 degree Celsius in an insulating vessels . final mass of water in vessel is [ specific heat of ice =0.5 cal /g/degree Celcius

Answer 1

m 1                 = 200 g

m 2                = 500 g

∑ m                = 700 g

T 1                  = -20 °c

T 2                 = 20 °c

Δ T                 = 20-(-20)

                      = 40 °c

S                    = 0.5 cal/g×T

Q                   = ?

 from,

           Q = mSΔT

               = 700×0.5×40

               = 14000 cal  

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Answer 2

Answer:

I hope u understand

Explanation: