Question

200 g of marble chips (CaCO3) are dropped into
365 g of hydrochloric acid. The amount of chips
dissolved will be.

Caco3+2HCl -)CaCl + H2O + CO2

(1) 200 g
(2) 137 g
(3) 100 g
4) 71g​

Answer 1

Answer:

(1) 200gm is the right answer

Answer 2

Answer:

Explanation:

"The ratio of mole between CaCO₃ and both CaCl₂ and CO₂  formed is 1:1. Since the mole of the CaCO₃ then the mole of the CaCl₂ and CO₂ 2 moles.

Calculation of the mass of the products :

Mass of 2 moles CaCl₂, molar mass 111 g/mol

Mass = moles ×molar mass

          = 2 moles × 111g/mol

          = 222 g

ii) Mass of 2 moles CO₂, molar mass 44g/mol

Mass = moles × molar mass

        =  2 moles × 44g/mol

        =  88g

The mass of the CaCl₂ formed is 222g

While the mass of the CO₂ formed is 88g

Note: All the marble chips are absorbed (200g of it)

"