Question

200 g of water at 30°C is mixed with an equal amount of water at 60°C. Then resultant tempera-
ture of the mixture is [ ]
1) 45°C 2) 90°C 3) 50°C 4) 48°C

Answer 1

Answer:

30'c

Explanation:

give me star. and rhanks

Answer 2

Answer:This may help you

Explanation:

Here, Mass of water m

w

​

=100g

Mass of ice, m

i

​

=10g

Specific heat of water,S

w

​

=1calg

−1

o

C

−1

Latent heat of fusion of ice,L

fi

​

=80calg

−1

Let T be the final temperature of the mixture.

Amount of heat lost by water

=m

w

​

s

w

​

(△T)

w

​

=100×1×(50−T)

Amount of heat gained by ice

=m

i

​

L

fi

​

+m

i

​

s

w

​

(△T)

i

​

=10×80+10×1×(T−0)

According to principle of calorimetry:

Heat lost = Heat gained

100×1×(50−T)=10×80+10×1×(T−0)

500−10T=80+T

11T=420orT=38.2

o

C