Question

200 gram of ice at -20°C is mixed with 500 gram of water at 20°C in an insulating vessel final mass of water in the vessel is

(Ans. 600g)

Please don't post irrelevant answers.

Answer 1

Answer:

Explanation:

200 gram of ice at -20°C is mixed with 500 gram of water at 20°C in an insulating vessel.

Firstly, the ice will absorb energy from the water. It will result in rise in temperature of ice and fall in temperature of water. Since ice is less in quantity and its specific heat is less than water, the ice will reach 0 degree celsius.

Then the ice will start melting by absorbing energy from water. This will lead to formation of water from ice and further decrease of temperature of water till 0 degree. At that point, the system will be in thermal equilibrium as everything will be at 0 degree.

Specific heat capacity of water and ice are 4.187 J/gK and 2.108 J/gK respectively.

heat gained by 200g ice at -20°C to come to 0°C = 2.108*200 = 421.6J

Heat lost by 500g water at 20°C to come to 0°C = 4.187*500 = 2093.5J

So heat used for melting ice = 2093.5 - 421.6 = 1671.9 J

Latent heat of fusion of ice = 334 J/g

mass of ice melted by 1671.9 J = 1671.9/334 = 5g

Thus final mass of water = 500+5 = 505g

final mass of ice = 200-5 = 195g