Question

200 grams of a soil is taken and dried completely in bright sunshine. The mass of
dried soil is found to be 170 grams. Calculate the percentage of water (or moisture) present in the given
sample of the soil.​

Answer 1

15% is the answer
Hope it helps

Answer 2

$\bold{In \: this \: case :} \\ </p><p></p><p> \bold{Original \: mass \: of \: soil=170g} \\ \bold{Mass \: of \: dried \: soil=170g} \\ \bold{So, \: \: \: \: \: Mass \: of \: water \: in \: soil \: =200-170} \\ \bold{ \: \: \: \: \: \: \: \: \: \: =30g}$

$\bold{We \: know \: that:} \\ \bold{Percentage \: of \:water \: in \: soil \: = \: \frac{Mass \:of \: water \: in \: soil \: }{Original \: massof \: soil \: } \times 100}$

$\: \: \: \: \: \: \: \: \bold{ = \frac{30g}{200g} \times 100} \\ \: \: \: \: \bold{ = \frac{30}{2} } \\ \: \: \: \: \: \: 15 \: per \: cent$

Thus, the given sample of soil contains 15 per cent water in it. We can also say that the given sample of soil contains 15 per cent moisture in it. By saying that a soil contains 15 per cent water, we mean that 100 grams of this soil contains 15 grams of water.