200 kg car traveling at 10 m/s hits a tree and is brought to rest in 0.10s. What is the magnitude of the average force acting on the car to bring it to rest?
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Answered by
8
Answer:
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Explanation:
Given: mass = 1200 kg, vo=10m/sec , time = .1 sec
vf=vo+a⋅t
0=10+a⋅.1
a = -100 m/sec
F = m x a
F = 1200 x -100, ==> F = -120000 N (- sign indicted in the opposite direction)
>>>>>> F = -120000 N (- sign indicted in the opposite direction)
Answered by
1
Answer:
Explanation:
1.2×10*2
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