Question

200 kg of rice was distributed amongst A, B and C in the ratio 4:7:9. How much does each
get?​

Answer 1

Step-by-step explanation:

ʀᴀᴛɪᴏ = 4:7:9 = 20

$a \: = \frac{200 \times 4}{20} = 40kg$

$b \: = \: \frac{200 \times 7}{20} = 70kg$

$c \: = \: \frac{200 \times 9}{20} = 90kg$

ᴛʜᴜꜱ , ᴀ ʙ & ᴄ ɢᴇᴛꜱ 40ᴋɢ , 70ᴋɢ & 90ᴋɢ ᴏꜰ ʀɪᴄᴇ ʀᴇꜱᴘᴇᴄᴛɪᴠᴇʟʏ

⭐✨hope it's help you✨⭐

Answer 2

Answer:

Given:-

200 kg of rice was distributed amongst A, B and D in the ratio 4:7:9. How much does each get ?

To Find:-

How much does each get.

Note:-

●》When A,B and C is added; we will get 200 kg

●》When we rearranged a term from one side to another~

+ becomes -

- becomes +

× becomes ÷

÷ becomes ×

Solution:-

☆ We don't know the exact number of A,B and C; so let them consider as "x"; so it will be~

♤ A = 4x , B = 7x and C = 9x

☆ According to note first point~

▪︎$A + B + C = 200 kg$

▪︎$4x + 7x + 9x = 200 kg$

▪︎$20x = 200 kg$

☆ According to note second point ( rearrangement ), 20x is in multiple form; so~

▪︎$x = 200 kg ÷ 20$

☆ After doing calculations~

▪︎$x = 10 kg$

__________________________________

♤ So now~

▪︎$A -> 4x => 4 × 10 kg = 40 kg$

▪︎$B -> 7x => 7 × 10 kg = 70 kg$

▪︎$C -> 9x => 9 × 10 kg = 90 kg$

Answer:-

A gets = 40 kg

B gets = 70 kg

C gets = 90 kg

:)