200 logs are stacked in the following manner 20 logs in boltom, ,
1,9 the next row, 18 in the row next to it soon in how many rows are legs obtain and how many logs are in the top of row
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Answer:
It is an AP such that a=20 & d=−1
S
n
=200
⇒200=
2
n
[2(20)+(n−1)(−1)]
⇒400=n[40+1−n]
⇒n
2
−41n+400=0
⇒n
2
−25n−16n+400=0
⇒(n−25)(n−16)=0
So n=16 or n=25
T
16
=a+15d=20−15=5
T
25
=a+24d=20−24=−4
Since T
25
is not possible.
∴ n=16 & 5 logs are placed in the top row
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