Question

200 ml 0.1M Ca(OH)2+500ml 0.2N Hcl+100 ml 0.02M Al(OH)3 calculate ph

Answer 1

Answer:

Heya mate

Molarity=No of moles of solute [H+]/

Volume of solution

No of moles of [H+] for HCI=0.3*0.1=0.3

No. Of moles of [H+] for H2SO4 =0.2*2*0.3=0.12(since there are two moles H+ in a mole H2SO4

Total no. Of moles of [H+] =0.15

Total volume of solution =300 ml=0.3 L

Thus molarity =0.15/0.3=0.3=0.5moles/L

:)