Question

200 mL.0.2 M HCl is diluted to get 0.05 M HCl solution. Final volume of the solution is:

​

Answer 1

Answer:

Explanation:

Are u from Brilliant Pala?

Answer 2

Given:

200 mL of 0.2 M HCl is diluted to get 0.05 M HCl solution.

To find:

Final volume of the solution.

Calculation:

Let the final volume of solution be V2 and the strength of the solution be S2;

Applying the working formula for Titration:

$\boxed{\rm{ \therefore \: (V1)(S1) = (V2)(S2)}}$

$\rm{ = > \: 200 \times 0.2 = (V2) \times 0.05}$

$\rm{ = > \: 40 = (V2) \times 0.05}$

$\rm{ = > \: (V2) \times 0.05 = 40}$

$\rm{ = > \: (V2) = \dfrac{40}{0.05}}$

$\rm{ = > \: (V2) = \dfrac{4000}{5}}$

$\rm{ = > \: (V2) = 800 \: ml}$

So, final answer is:

$\boxed{ \red{ \large{ \sf{\: (V2) = 800 \: ml}}}}$