Chemistry, asked by stephenputhurpo, 8 months ago

200 ml 0.2 N KMnO4 solution oxidised
500ml H₂ C24 in acid medium find
normality of H2C2O4​

Answers

Answered by jyotirmoy2512
0

Answer:

N1V1=N2V2

0.2×200=500×N2

N2=0.2×200/500

=40/500

=0.08

Explanation:

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