Question

200 mL ethylene gas and 150
mL of HCl gas were allowed to react at 1
bar pressure according to the reaction
C2H4 (g) + HCl(g) ------> C2H5CI(g)
Calculate the PV work in joules.
slove in numerical from​

Answer 1

Answer:

Explanation:

C2h2

Hopes

Answer 2

Answer:

15.0 J

Explanation:

W = - Pext ∆V = - Pext (V2 - V1 )

According to the equation of reaction,

1 mole of C2 H4 reacts with 1 mole of HCl to produce 1 mole of C2 H5 Cl. Hence, 150 mL

of HCl would react with only 150 mL of C2 H4 to produce 150 mL of C2 H5 Cl.

V1 = 150 mL + 150 mL = 300 mL = 0.3 dm3

V2 = 150 mL = 0.15 L, Pext = 1 bar

Substitution of these quantities in above

W = -1 bar (0.15 dm^3 - 0.3 dm^3 ) = 0.15 dm3 bar

= 0.15 dm^3 bar × 100 J /dm^3 bar

= 15.0 J