Question

200 ml N/10 H2SO4 is mixed into 300 ml N/100 NaOH. Calculate normality of resulting mixture.

Answer 1

Answer: 0.034 N

Explanation: Normality : It is defined as the number of gram equivalents of solute present in one liter of solution.

Formula used :$\text{no of gram equivalents of}H_2SO_4=\text{Normality}\times \text{Volume in L}=0.1\times 0.2L=0.02$

$\text{no of gram equivalents of }NaOH=\text{Normality}\times \text{Volume in L}=0.01\times 0.3L=0.003$

0.003 gram equivalents of $NaOH$ neutralize 0.003 gram equivalents of $H_2SO_4$.

Thus (0.02-0.003)=0.017 gram equivalents of $H_2SO_4$ remains in 500 ml of solution.

$Normality=\frac{\text{number of gram equivalents}}{\text{volume of solution in L}}$

$Normality=\frac{0.017}{0.5L}=0.034N$

Answer 2

Answer:

0.034

Explanation:

use the formula of that