Question

200 ml N/10 H₂SO₄ is mixed into 300ml N/100 NaOH. Calculate normality of resulting mixture.​

Answer 1

Answer:

Use N1V1 + N2V2= N Vtotal.. here as one is giving H+ nd one OH-, so we will use 200*1/10-300*1/100=N*300, N=0.034

Answer 2

Here is ur answer:

N×500= $\frac{1}{10} \times 200 - \frac{1}{100} \times 300$

i.e., N×500= 17

∴ N= 0.034

Hope this will help you ❤