Question

200 ml of 0.2 molar hcl solution is added to 300 ml of 0.3 molar hcl solution calculate the final molarity

Answer 1

Answer:

0.26M

Explanation:

Quantity of solution = 200ml and 300 ml

Hcl = 0.2 moles and 0.3 moles

Molarity = no of moles of solute[H+]/ volume of the solution

No of moles of [H+] for HCl = 0.2 × 0.2 = 0.04

No of moles of [H+] for HCL= 0.3 × 0.3 = 0.09

Total no of moles of [H+] = 0.04 + 0.09 = 0.13

Total volume of solution = 300ml + 200 ml = 500ml = 0.5L

Thus Molarity = 0.13/0.5

= 0.26 moles/L

Thus, the final molarity of the solution is 0.26M