Question

200 mL of an aqueous solution of a protein contain
its 1.26 g. The Osmotic pressure of this solution
at 300 K is found to be 2.57 x10-3 bar. The molar
mass of protein will be :-
(R = 0.083 L bar mot1 K-1)​

Answer 1

in concept

Mathematical Expression for Osmotic Pressure -

\pi =CRT

 

- wherein

\pi = Representation of osmotic pressure.

C =constant\: in \: moles

R =Gas \: constant= 0.0821\frac{atm.lit}{mol.k}

T=Temp. \: in\: kelvin

 

Osmotic pressure, \pi\:=\:CRT

2.57\times 10^{-3}=C\times 0.083\times 300

C = 10^{-4}\:mol\:L^{-1}\times 1.0321

\frac{1.26}{M\times 0.2}\:=\:10^{-4}

M = 61038\:g\:mol^{-1}

Option 4)

61038 g mol-1

This option is correct.