200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57 × 10⁻³ bar. The molar mass of protein will be (R = 0.083 L bar mol⁻¹ K⁻¹)
(a) 51022 g mol⁻¹
(b) 122044 g mol⁻¹
(c) 31011 g mol⁻¹
(d) 61038 g mol⁻¹
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Option C is the correct answer
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