Question

200 ml of C2H4 is burnt in just sufficient air. Calculate the resulting mixture composition at 100 degree celcius and 760 mm of Hg

Answer 1

First analyze combustion of 50 cm3 CH4

CH4 + 2O2 -> CO2 + 2H2O

That will give you

50 cm3 of O2 used by C, and 50 cm3 used by H.

Then, analyze

C2H4 +3O2-> 2CO2+2H2O

because C2H4 in the same volume contains twice amount of C than CH4, its C content will use twice amount of O2 than C in CH4. So it needs 100 cm3 of O2 for C in C2H4.

Similarly, we can deduce that O2 volume used by H in C2H4 will be the same as for CH4, that is 50 cm3.

Together it will need 250 cm3 of O2 to do the job.

Answer 2

Answer:When O2 is 600ml. N2 is (80×600)÷20 = 2400ml

Explanation:Hence the composition of the resultant mixture is

CO2 = 400ml

N2 = 2400ml

H2O = 400 ml