Question

200 ml of hard water was boiled with 100 ml of Na2CO3 reagent. After boiling the solution was again made to 200 ml and filtered. 25 ml of the filtrate required 8.2 ml of HCI for neutralization. The permanent hardness of given hard water sample is​

Answer 1

Answer:

n(Hcl)= 25/22,4

=1.12

n(Hcl)=m/M

1.12=m/36.5

m=40.88g