200 ml of M/4 hcl solution was diluted to make it M/10 hcl solution.volume of h2o needed for dilution is
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Answer:
The volume of M/4 HCl, V1 = 200 ml
Let the volume of M/10 HCl be “V2”, the Molar mass of M/4 HCl be “M1”=M/4 and the molar mass of M/10 HCl be “M2”=M/10.
We know that, the volume of M/10 HCl is obtained by diluting or adding some amount of water in the M/4 HCl.
So, let V2 = Volume of water needed(Vw) + V1 …… (i)
Using the equation,
M1 * V1 = M2 * V2
Or, M1 * V1 = M2 * (Vw + V1)
Substituting the given values
∴ M/4 * 200 = M/10 * (Vw+200)
Or, Vw + 200 = 500
Or, Vw = 500 -200 = 300 ml
Hence, the volume of H₂O needed for dilution is 300ml.
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