Question

200 molecules of O2 will weigh how many molecules of SO3

Answer 1

Answer:

ANSWER

The weight of one SO

3

molecule =32+(3×16)

=32+48=80u

Weight of twenty SO

3

molecule =20×80=1600u

Weight of each molecule of oxygen=2×16=32u

Therefore, the no. of oxygen molecules =

32

1600

=50

So, the correct option is B

Answer 2

Therefore 200 molecules of O₂ will weigh '80' molecules of SO₃.

Given:

Number of O₂ molecules = 200

And molecules of SO₃ are given

To Find:

How many molecules of SO₃ will constitute 200 molecules of O₂.

Solution:

The given question can be solved very easily as shown below.

Given that number of 'O₂' molecules = 200

Atomic Weight of Oxygen 'O' = 16 u

Atomic Weight of Sulphur 'S' = 32 u

Weight of 1 molecule of O₂ = 2 × 16 = 32 u

Weight of 200 molecules of O₂ = 32 × 200 = 6400 u

Weight of O₃ molecule = 3 × 16 = 48 u

Weight of 1 molecule SO₃ = ( 32 + 48 ) = 80

Now [ 1 × x molecules ] of SO₃ will constitute 200 molecules of O₂

⇒ 80x = 6400

⇒ x = 6400 / 80 = 80

Therefore 200 molecules of O₂ will weigh '80' molecules of SO₃.

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