Question

200 = n/2 { 40 - n+1 }. Find 'n'?​

please reply...

Answer 1

Step-by-step explanation:

200= n/2 [40-n+1]

400= n[41-n]

400= 41n-n^2

n^2-41n+400=0

By -b±√b^2-4ac/2a formula

n = 25 (or) 16

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