Question

200 newton of retardative force is acting on a body or mass 20 kg , which is moving initially with a speed of 15 ms ^-1 . How long does the body take to stop? ​

Answer 1

Answer:

The answer is 2/3

Explanation:

because the 200÷20= 10

10/15=2/3

Answer 2

GIVEN:

force=200 N

mass=20 kg

initial velocity (u)= 15 m/s

final velocity ( v)=0

TO FIND:

Time=??

SOLUTION:

$f = ma \\ a = \frac{200}{20} \\ a = 10 \frac{m}{ {s}^{2} }$

$v = u + at \\ v = u - at(decceleration) \\ u = at \: (v = 0) \\ t = \frac{15}{10} \\ t = 1.5 \: sec$

I hope this helps ( ╹▽╹ )