2000 candidates appear in a written test in mathematics and general awareness for a government job.1800 passed in at least one subject. If 1200 passed in mathematics and 1500 in general awareness .find how many passed in mathematics only ?
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Step-by-step explanation:
- 2000 candidates appeared in a written test in mathematics and general awareness.
- 1800 passed in at least one subject.
- 1200 passed in mathematics
- 1500 passed in general awareness.
- The number of candidates passed in only mathematics.
Let M be the number of candidates passed in Mathematics.
And GA be the number of candidates passed in General Awareness.
1800 students passed in at least 1 subject.
So:-
M U GA = 1800 [U = union]
Candidates passed in only Mathematics = 1200
→ M = 1200
Candidates passed only in General awareness = 1500
→ GA = 1500
→ M + GA = 1200 + 1500 = 2700
Number of students passed in both
= (M + GA) - (M U GA)
= 2700 - 1800
= 900
∴ Number of candidates passed in both = 900
∴ M ⋂ GA = 900
Number of candidates passed only in Mathematics.
= M - (M ⋂ GA)
= 1200 - 900
= 300
∴ 300 candidates are passed only in Mathematics
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