2000 joule of work is done in sliding a 2kg block up an inclined plane of height 20. Taking g= 10m/s² work done against friction is
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We know that
Work = mgh
⇒ work done = 2 × 10 × 20
⇒ work done = 400 j
Work = mgh
⇒ work done = 2 × 10 × 20
⇒ work done = 400 j
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