2002 sin +0100 cos what is ans
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Answer:
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Given
2cos10
o
+sin100
o
+sin1000
o
+sin10000
o
By using trigeometric property
sin(
2
nπ
+θ)=cosθ [there n=odd]
we get
⇒ 2cos10
o
+sin(90+10
o
)+sin(90×11+10
o
)+sin(90×111+10
o
)
⇒ 2cos10
o
+cos10
o
+cos10
o
+cos10
o
⇒ 5cos10
o
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