Question

200cm³ of an aqueous solution of a protein contains 1.26g of the protein. The osmotic pressure of such solution at 300K is found to be 2.57 X 10-³ bar. Calculate the molar mass of the protein.?

Answer 1

Answer:

60,990.36 g/mol is the molar mass of the protein.

Explanation:

Volume of the solution = $200 cm^3$= 200 mL =0.200 L

Mass of the protein = 1.26 g

Molar mass of protein = M

Temperature of the solution = T = 300 K

Osmotic pressure of the solution =$\pi=2.57\times 10^{-3} bar=0.0025 atm$

$\pi=cRT$

$\pi=\frac{Moles}{Volume(L)}RT$

$0.0025 atm=\frac{Moles}{0.200 L}\times 0.0821 atm L/mol K\times 300 K$

$Moles = 2.059\times 10^{-5} moles$

$2.059\times 10^{-5} moles=\frac{1.26 g}{M}$

M = 60,990.36 g/mol

60,990.36 g/mol is the molar mass of the protein.

Answer 2

Hope it helps

And it's not a copy I have posted this on other site also.