Chemistry, asked by Surajkatwal, 1 year ago

200cm³ of an aqueous solution of a protein contains 1.26g of the protein. The osmotic pressure of such solution at 300K is found to be 2.57 X 10-³ bar. Calculate the molar mass of the protein.?

Answers

Answered by IlaMends
81

Answer:

60,990.36 g/mol is the molar mass of the protein.

Explanation:

Volume of the solution = 200 cm^3= 200 mL =0.200 L

Mass of the protein = 1.26 g

Molar mass of protein = M

Temperature of the solution = T = 300 K

Osmotic pressure of the solution =\pi=2.57\times 10^{-3} bar=0.0025 atm

\pi=cRT

\pi=\frac{Moles}{Volume(L)}RT

0.0025 atm=\frac{Moles}{0.200 L}\times 0.0821 atm L/mol K\times 300 K

Moles = 2.059\times 10^{-5} moles

2.059\times 10^{-5} moles=\frac{1.26 g}{M}

M = 60,990.36 g/mol

60,990.36 g/mol is the molar mass of the protein.

Answered by Yash8564862253
34

Hope it helps

And it's not a copy I have posted this on other site also.

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