Question

200g of a soil is taken and dried completely in bright sunshine.The mass of dried soil is found to be 170g. Calculate the percentage of water present in the given soil

Answer 1

200-170 so 30 is the ans

Answer 2

Answer:

$\bold{In \: this \: case :} \\ </p><p></p><p> \bold{Original \: mass \: of \: soil=170g} \\ \bold{Mass \: of \: dried \: soil=170g} \\ \bold{So, \: \: \: \: \: Mass \: of \: water \: in \: soil \: =200-170} \\ \bold{ \: \: \: \: \: \: \: \: \: \: =30g}$

$\bold{We \: know \: that:} \\ \bold{Percentage \: of \:water \: in \: soil \: = \: \frac{Mass \:of \: water \: in \: soil \: }{Original \: massof \: soil \: } \times 100}$

$\: \: \: \: \: \: \: \: \bold{ = \frac{30g}{200g} \times 100} \\ \: \: \: \: \bold{ = \frac{30}{2} } \\ \: \: \: \: \: \: 15 \: per \: cent$

Thus, the given sample of soil contains 15 per cent water in it. We can also say that the given sample of soil contains 15 per cent moisture in it. By saying that a soil contains 15 per cent water, we mean that 100 grams of this soil contains 15 grams of water.