Question

200g of ice at 0c convert into water at 0c in 1 min when heat is supplied to it at constant rate in his much time 200g of water at 0c will change to 20c. specific heat of ice=336J\g​

Answer 1

Answer:

$\boxed{\sf Time \ required = 15 \ s}$

Given:

Amount of ice melted from 0°C ice to 0°C water (m) = 200 g

Specific heat capacity of ice (L) = 336 J/g

Time taken for ice to convert into water (t) = 1 min = 60 seconds

Specific heat capacity of water (C) = 4.2 J/g

To Find:

Time required to convert 200g of water at 0°C to 20°C when heat is supplied to it at a constant rate.

Explanation:

• $\sf Heat \: supplied \: to \: melt \: ice = mL$

$\sf = 200 \times 336$

$\sf = 67200 \: J$

• $\sf Rate \: of \: heat \: supply \: (Q) = \frac{Heat \ supplied}{Time taken}$

$\sf = \frac{67200}{60}$

$\sf = 1120 J/s$

• $\sf Heat \: required \: to \: heat \: water \: from$

$\sf 0 ^ \circ C \: to \: 20^ \circ C:$

$\sf Heat \: required = mC \Delta T$

$\sf = 200 \times 4.2 \times (20 - 0)$

$\sf = 840 \times 20$

$\sf = 16800 \: J$

• $\sf Time \: required = \frac{Heat \ required}{Rate \ of \ heat \ supply}$

$\sf = \frac{16800}{1120}$

$\sf = 15 \: s$

$\therefore$

Time required to convert 200g of water at 0°C to 20°C when heat is supplied to it at a constant rate = 15 seconds