Question

200g of water at 30 degrees Celsius is mixed with an equal amount of water at 60 degrees Celsius then resultant temperature of the mixture is
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Answer 1

Answer:

45°c

Explanation:

heat absorb by cold water = heat reduced by hot water

Answer 2

Thus the resultant temperature of the mixture is 45°C.

Explanation:

Given data:

• Mass of water "m"= 200 g

• Initial temperature "T" = 30°C

• Mass of water m' = 200 g

• Second temperature = 60°C

Formula:

Delta Q = (m1 x T1 ) + (m2 + T2) / total mass

Delta Q =  (200 g x 30) + (200 x 60 ) / 400

Delta Q = 6000 + 12000 / 400

Delta q = 45°C

Thus the resultant temperature of the mixture is 45°C