Question

200j of heat is produced in one second from a resistor of resistance 8 ohm find the potential difference across the resistor and its power​

Answer 1

potential difference  across the two point is 40 volt.

power  =200 watt

Explanation:

heat                =      200 joule

time                =       1 second

resistance      =       8 ohm

heat               =       $I^{2}RT$

 $I^{2}$                  =        H / RT

 I                    =        $\sqrt{H / Rt}$

 I                    =        $\sqrt{200 / 8}$

 I                    =         $\sqrt{25}$

 I                    =          5 ampere

now,

v                    =         IR

v                    =       5 * 8

v                    =       40 volt

now,

power            =        potential  difference *   current      

 P                   =         V     *     I

 P                   =        40    *    5

 P                   =        200 watt

potential difference:-

The potential difference is between 2 points in a current carrying conductor when the electric current passes.So we can define the potential difference in such a way that require a work done moving  on a unit positive charge from one place  to another place  is called a potential difference.

power :- The amount of electricity that an electronic device spends in working, we call it power.

si unit electric power is watt.

Answer 2

Aɴꜱᴡᴇʀ

$\red{\tt{\therefore \: Potential \: Difference \: across \: Resistor \: is \: 31.62 \: Volts}}$

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Gɪᴠᴇɴ

Heat Energy (H) = 200 J

Resistance (R) = 5 ohm

Time (t) = 1s

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ᴛᴏ ꜰɪɴᴅ

Potential Difference across the resistors and it's power

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Sᴛᴇᴘꜱ

Use formula for Heat Energy :

$\begin{lgathered}\dashrightarrow \boxed{\sf{H \: = \: \dfrac{V^2}{R}t}} \\ \\ \dashrightarrow \tt{200 \: = \: \dfrac{V^2}{5} \: \times \: 1} \\ \\ \dashrightarrow \tt{V^2 \: = \: 200 \: \times \: 5} \\ \\ \dashrightarrow \tt{V^2 \: = \: 1000} \\ \\ \dashrightarrow \tt{V \: = \: \sqrt{1000}} \\ \\ \dashrightarrow \tt{V \: = \: 31.62} \\ \\ \pink{\sf{\therefore \: Potential \: Difference \: across \: Resistor \: is \: 31.62 \: Volts}}\end{lgathered}$

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$