Question

200ml of .1 M AgNo3is mixed with .2M Nacl. Find concentrate of cl- in result ing solution if precipitate is form end

Answer 1

Answer:

mark as brainliest

Explanation:

The concentration of Cl- in the resulting solution is equal to 0.08 M.

The number of moles of NaCl is equal to 0.06 (0.3*0.2)

The number of moles of AgNO3 is equal to 0.02 (0.2*0.1)

One mole of AgNO3 reacts with one mole of NaCl to precipitate out one mole of AgCl.

AgNO3 is the limiting reagent, so number of moles of AgCl precipitated is equal to 0.02, which implies that 0.02 moles of NaCl is used up.

Mole of NaCl remaining is equal to 0.04 (0.06-0.02)

Total volume of the solution is equal to 500 mL.

Hence molarity of NaCl, which will be equal to the molarity of Cl- ions ia equal to 0.08 M (0.04*1000/500)