Question

200mL of 1M oxalic acid is diluted with water to make the solution 2L, the molrity of resulting solution is​

Answer 1

Here, Let M

1

(molarity H

2

SO

4

)=2M, V

1

(volume of H

2

SO

4

)=20ml=0.02L, V

2

(volume of solution)=1L and M

2

(molarity of resulting solution)=?

Therefore, M

1

×V

1

=M

2

×V

2

M

2

=0.04M

Normality=M

2

×n , here n is number of H

+

ions an acid can donate

Normality=0.04×2=0.08N