Question

200ml of 2m ca(oh)2 is mixed with 300ml of 1 m hcl in vessel find the nature of resulting solution?

Answer 1

Explanation:

Correct option is A)

Moles of HCl= 6×0.300+1×0.200=2 mol.

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H +

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H + ] ion =

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H + ] ion = 1

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H + ] ion = 12

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H + ] ion = 12

Moles of HCl= 6×0.300+1×0.200=2 mol.Volume of the solution is 1 L.So, molar concentration of [H + ] ion = 12 =2 M.