Question

200ml of pure oxygen is subjected to electric discharge, 15%of oxygen is converted into ozone. the volume of ozonized oxygen is

Answer 1

your answer is 30 ml

Answer 2

Answer:

The volume of ozonized oxygen is 30 mL.

Explanation:

$3O_2(g)\rightarrow 2O_2(g)$

Volume of oxygen = 200mL

Percentage of oxygen converted to ozone = 15%

Volume of ozone formed = V

$15\%=\frac{V}{200 mL}\times 100$

$V=\frac{15}{100}\times 200 mL=30 mL$

The volume of ozonized oxygen is 30 mL.