Question

200ml of water is added to 1 litre of 0.6M HNO3 solution.what is the molarity of dilute solution.(ans:0.5)​

Answer 1

Given:-

• Initial molarity of the solution = 0.6 M

• Initial volume of the solution = 1 L

• Volume of water added for dilution = 200 mL

To find:-

• Molarity of the dilute solution.

Solution:-

Firstly, let's convert the volume of water used for dilution from mL to L.

⇒ 1 mL = 0.001 L

⇒ 200 mL = 200(0.001)

⇒ 0.2 L

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Volume of the solution after dilution :-

= 1 L + 0.2 L

= 1.2 L

Now, we know the dilution formula :-

M₁V₁ = M₂V₂

Where :-

• M₁ is the initial molarity.

• V₁ is the initial volume.

• M₂ is the molarity after dilution.

• V₂ is the volume after dilution.

Substituting values, we get :-

⇒ 0.6 × 1 = M₂ × 1.2

⇒ 0.6 = 1.2M₂

⇒ M₂ = 0.6/1.2

⇒ M₂ = 0.5 M

Thus, molarity of the dilute solution is 0.5M .

Answer 2

Answer:

• Initial molarity of the solution = 0.6 M

• Initial volume of the solution = 1 L

• Volume of water added for dilution = 200 mL

To find:-

• Molarity of the dilute solution.

Solution:-

Firstly, let's convert the volume of water used for dilution from mL to L.

⇒ 1 mL = 0.001 L

⇒ 200 mL = 200(0.001)

⇒ 0.2 L

________________________________

Volume of the solution after dilution :-

= 1 L + 0.2 L

= 1.2 L

Now, we know the dilution formula :-

M₁V₁ = M₂V₂

Where :-

• M₁ is the initial molarity.

• V₁ is the initial volume.

• M₂ is the molarity after dilution.

• V₂ is the volume after dilution.

Substituting values, we get :-

⇒ 0.6 × 1 = M₂ × 1.2

⇒ 0.6 = 1.2M₂

⇒ M₂ = 0.6/1.2

⇒ M₂ = 0.5 M

Thus, molarity of the dilute solution is 0.5M .

hope this helps you!!

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